FAQ
Q.
How much output power (current) can actually be used?
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A. The specifications stipulate the maximum output current and maximum output power. It is necessary to use the products under conditions where none of these figures are exceeded so that it can be operated safely.
Please note that they will be as shown below particularly when using an output voltage variable function.

(1) When the output voltage is equal to the rated output voltage (initial settings)
  The maximum output power = the maximum output current × the rated output voltage so there is no problem if it is confirmed that one of them is not exceeded.

(2) When setting the output voltage higher than the rated output voltage
  The maximum output power < the maximum output current × the set output voltage so it is limited with the maximum output power (the output current must be decreased).

(3) When setting the output voltage lower than the rated output voltage
  The maximum output power > the maximum output current × the set output voltage so it is limited with the maximum output current (the output power must be decreased).

Output derating by operating temperature is also specified for each product. This must also be taken into consideration along with the other factors.

Example) The maximum output current is 2A and the maximum output power is 10W under the specifications if the output voltage of the CC10-4805SF-E is adjusted to 6V with an ambient temperature of 85°C and convection cooling is used, but the output current is decreased so that it does not exceed the maximum output power when the output voltage is set higher than the rated output voltage.
It is necessary to make a further decrease down to 40% or below during use with an ambient temperature of 85°C with output derating.
Therefore, the maximum output current is as follows:
Maximum output current = maximum output power ÷ set output voltage × 0.4 = 10 ÷ 6 × 0.4 = 0.66A

Figure 1

Figure 1